Answer:
[tex]P_4_{(I)}+5O_2_{(g)}+6H_2O_{(l)}\rightarrow +4H_3PO_4_{(l)}[/tex]
Explanation:
The first step is:
[tex]P_4_{(I)}+5O_2_{(g)}\rightarrow 2P_2O_5_{(g)}[/tex]
Second step is:
[tex]P_2O_5_{(g)}+3H_2O_{(l)}\rightarrow 2H_3PO_4_{(l)}[/tex]
Multiplying second step by 2, and adding both the steps, we get that:
[tex]P_4_{(I)}+5O_2_{(g)}+2P_2O_5_{(g)}+6H_2O_{(l)}\rightarrow 2P_2O_5_{(g)}+4H_3PO_4_{(l)}[/tex]
Cancelling common species, we get that:
[tex]P_4_{(l)}+5O_2_{(g)}+6H_2O_{(l)}\rightarrow +4H_3PO_4_{(l)}[/tex]