Answer:
245.45km in a direction 21.45° west of north from city A
Explanation:
Let's place the origin of a coordinate system at city A.
The final position of the airplane is given by:
rf = ra + rb + rc where ra, rb and rc are the vectors of the relative displacements the airplane has made. If we separate this equation into its x and y coordinates:
rfX = raX+ rbX + rcX = 175*cos(30)-150*sin(20)-190 = -89.75km
rfY = raY + rbY + rcT = 175*sin(30)+150*cos(20) = 228.45km
The module of this position is:
[tex]rf = \sqrt{rfX^2+rfY^2} = 245.45km[/tex]
And the angle measure from the y-axis is:
[tex]\alpha =atan(rfX/rfY) = 21.45\°[/tex]
So the answer is 245.45km in a direction 21.45° west of north from city A