Answer:
The deuterium will have a larger radius of curvature, since it is more massive.
Explanation:
Suppose that the initial velocity of deuterium and protons is the same. According to the relation for centripetal acceleration:
[tex]F = \frac{mv^2}{r}[/tex]
The force is the same due to same electric charge between proton and deuterium. Solving for r:
[tex]r = \frac{mv^2}{F}[/tex]
It means that, the more the mass, the larger the radius due to the directly proportional relation.