Respuesta :
C + O2 -> CO2
Oxygen is the excess reactant (doesn’t get used up in reaction, therefore mass of o2 is irrelevant) so use carbon (the limiting reactant) to calculate the mass of CO2
u should get 48.4g
Oxygen is the excess reactant (doesn’t get used up in reaction, therefore mass of o2 is irrelevant) so use carbon (the limiting reactant) to calculate the mass of CO2
u should get 48.4g

Answer:
grams of CO2 produced = 48.4 grams
Explanation:
Write the balance equation of the reaction . The chemical equation is represented below
C(s) + O2(g) → CO2(g)
The equation is already balanced. From the reaction carbon is the limiting reagent and it is use in the computation of mass for the product . Oxygen is in excess.
C(s) + O2(g) → CO2(g)
atomic mass of carbon = 12 g/mol
atomic mass of oxygen = 16 g/mol
Molar mass of carbon dioxide = 12 + 16(2) = 12 + 32 = 44 grams
if 12 g of C produce 44 grams of CO2
13.2 grams of C will produce ? grams of CO2
cross multiply
grams of CO2 produced = (13.2 × 44)/12
grams of CO2 produced = 580.8/12
grams of CO2 produced = 48.4 grams