Answer:
[tex]v=-1.46 \ m/s[/tex]
Step-by-step explanation:
So, as balloon reaches its maximum height i.e. 11 m , its velocity become 0.
Therefore, [tex]v_{top}=0 \ m/s[/tex].
It is given that acceleration due to gravity should be taken as , [tex]g=-9.8 \ m/s^2[/tex].(because it direction is down)
Now it is also given that upward direction is positive and downward direction is negative. So velocity should be negative.
Using equation of motion,
[tex]v_{final}^2 - v_{initial}^2 =2\times a\times displacement[/tex] .....eqn 1.
where , displacement = -11 m(because it displace towards down) and [tex]a=g=-9.8\ m/s^2[/tex]
Putting these values in eqn 1 .
[tex]v_{final}^2-0^2 =2\times 9.8 \times 11[/tex]
[tex]v = \pm1.46 m/s.[/tex]
But as we know direction of velocity is downward.
Therefore, [tex]v=-1.46 \ m/s[/tex]
where negative sign indicates its direction is downward.
