Answer: V = ((780000-390000) / 3) x 2) + 780000 = 1040000.
Explanation:
0 1 2 3 4 5
780000 390000
If we know that two years after the purchase, an industrial mill is worth $ 780,000, and five years after the purchase, the machine is worth $ 390,000.
780000 - 390000 = 390000 depreciation contained in periods 3.4 5.
Since the depreciation is linear, 390000/3 = 130000 is the depreciation contained in each of those 3 periods. And it will be the one contained in the first two periods.
If two years after the purchase the industrial mill is worth 780000.
780000 + 130000x2 = 1040000.
The formula is summarized in:
V = ((780000-390000) / 3) x 2) + 780000 = 1040000.