Answer:
T = 2390 degree C
Explanation:
Given data:
Resistance 12 ohm
Temperature 20 degree C
[tex]Resistance _{HOT} = 140 ohm[/tex]
we know that linear relation between the resistance and temperature is given as[tex]R = R_O[ 1+ \alpha ( T - T_o)][/tex]
where [tex]R_O[/tex] is resistance at [tex]_o,[/tex] and [tex]\alpha[/tex] = coefficient of resistivity
[tex]140 = 12 \times ( 1 + 0.0045 \Delta T}[/tex]
SOLVING FOR [tex]\Delta T[/tex]
[tex]\Delta T = 2370[/tex] degree C
WE KNOW
[tex]\Delta T = T - T_o[/tex]
T = 2370 + 20
T = 2390 degree C
