Answer:
[CO] = 7.61x10⁻³M
7.61x10⁻³x10³ = 7.61
Explanation:
For a generic equation aA + bB ⇄ cC + dD, the constant of equilibrium (Kc) is:
[tex]Kc = \frac{[C]^cx[D]^d}{[A]^ax[B]^b}[/tex]
We need to know the molar concentrations in the equilibrium. In the beginning, there is only COCl₂, and its concentration is the number of moles divided by the volume:
[COCl₂] = 7.73/10.0 = 0.773 M
So, the equilibrium will be:
COCl₂(g) ⇆ CO(g) + Cl₂(g)
0.773 0 0 Initial
-x +x +x Reacts
0.773-x x x Equilibrium
Supposing that x<<0.773, then:
[tex]Kc = \frac{x*x}{0.773}[/tex]
7.5x10⁻⁵ = x²/0.773
x² = 5.7975x10⁻⁵
x = √5.7975x10⁻⁵
x = 7.61x10⁻³ M
The supposing is correct, so [CO] = 7.61x10⁻³ x 10³ = 7.61
The concentration of CO is 0.008 M.
The equation is shown as; : COCl2 (g) ⇋ CO (g) + Cl2 (g) Kc = 7.5 x 10-5
The initial concentration of the phosphogen gas is obtained from;
concentration = number of moles/volume
Number of moles = 7.73 mol
volume = 10.0 liter
concentration = 7.73 mol/10.0 liter = 0.773 M
Setting up the ICE table, we have;
COCl2 (g) ⇋ CO (g) + Cl2 (g)
I 0.773 0 0
C -x +x +x
E 0.773 - x x x
Kc = [CO] [Cl2]/[COCl2]
7.5 x 10^-5= x^2/0.773 - x
7.5 x 10^-5(0.773 - x) = x^2
5.8 x 10^-5 - 7.5 x 10^-5x = x^2
x^2 + 7.5 * 10^-5x - 5.8 * 10^-5 = 0
x= 0.008 M
Now;
x = [CO] = [Cl2] = 0.008 M
The concentration of CO is 0.008 M.
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