Respuesta :
Explanation:
Relation between work, pressure and volume is as follows.
W = [tex]-P \Delta V[/tex]
where, W = work = -927 J (as energy is released so, work is done by the system)
P = pressure = 656 torr
= [tex]8.74 \times 10^{4}[/tex] Pa (as 1 torr = 133.3 Pa)
Initial volume [tex](V_{1})[/tex] = 42 [tex]cm^{3}[/tex]
= [tex]42 \times 10^{-6} m^{3}[/tex] (as 1 m = 100 cm)
Hence, calculate the final volume as follows.
W = [tex]-P \Delta V[/tex]
-927 J = [tex]-8.74 \times 10^{4} Pa \times (V_{2} - 42 \times 10^{-6} m^{3})[/tex]
[tex]106.06 \times 10^{-4} = V_{2} - 0.42 \times 10^{-4}[/tex]
[tex]V_{2}[/tex] = [tex]106.48 \times 10^{-4} m^{3}[/tex]
= 10.6 L (as 1 [tex]m^{3}[/tex] = 1000 L)
= 11 L (approx)
Thus, we can conclude that the gases expand 11 L against a constant pressure of 656 torr.
