Answer:
force exerted by the cat is 693 N
Explanation:
We know that total energy is the sum of work done by gravity and friction i.e.[tex]E = W_{gravtiy} + W_{friction}[/tex]
[tex]0 = mg (h+s) + Fs[/tex]
solving for F
[tex]F = - \frac{mg(h+s)}{s}[/tex]
here -ve sign indicate work done in opposite direction
where, m is mass of cat = 4.00 kg
h = 2.00 m, [tex]s = 12.00\times 10^{-2} m[/tex]
Putting all value in above equation
[tex]F = \frac{4 \times 9.87 \times( 2 + 12\times 10^{-2}}{12\times 10^{-2}}[/tex]
F = 692.53 N = 693 N
Therefore force exerted by the cat is 693 N
