In the simple Bohr model of the eighth excited state of the hydrogen atom, the electron travels in a circular orbit around a fixed proton. The radius of the orbit is 4.28 ✕ 10−9 m, and the speed of the electron is 2.43 ✕ 105 m/s. The mass of an electron is 9.11 ✕ 10−31 kg. What is the force on the electron (in N)? (Enter the magnitude.)

Respuesta :

Answer:

Net force on electron will be [tex]12.568\times 10^{-12}N[/tex]            

Explanation:

We have given that the orbit [tex]r=4.28\times 10^{-9}m[/tex]

Speed of the electron [tex]v=2.43\times 10^5m/sec[/tex]

Mass of the electron is given as [tex]m=9.11\times 10^{-31}kg[/tex]

Centripetal acceleration is given by [tex]a_c=\frac{v^2}{r}=\frac{(2.43\times 10^5)^2}{4.28\times 10^{-9}}=1.3796\times 10^{19}m/sec^2[/tex]

Force is given by F = ma

So force [tex]F=9.11\times 10^{-31}\times 1.3796\times 10^{19}=12.568\times 10^{-12}N[/tex]