Answer:
The equipment will cost $1740.
Step-by-step explanation:
Let the Cost of equipment, furniture and decoration be x, y and z.
Now, According to question,
x + y + z = 3600 ...... (1) (cost of all items)
x = 500 + y (∵ equipment cost 500 more than furniture)
and y = 2z ( ∵ furniture twice as much as decoration)
so, z = y/2
Now substituting the value of x and z in eq (1)
[tex] x + y + z = 3600[/tex]
[tex]500 + y + y + \frac{y}{2} = 3600[/tex]
[tex]2y + \frac{y}{2} = 3600 - 500[/tex]
[tex]\frac{5y}{2} = 3100[/tex]
[tex]y = \frac{3100\times 2}{5} = 1240[/tex]
So, the cost of furniture (y) = 1240
∴ Cost of equipment = y + 500 = 1240 + 500 = 1740
Therefore the cost of equipment was $1740.