Answer:
A) slope of equation 3x+4y-12=0 is m= [tex]-\frac{3}{4}[/tex] and y-intercept is 3
B) slope of equation 2x+y=1 is m=-2 and y-intercept is 1.
C) slope of equation 2x-y=0 is m=2 and y-intercept is 0.
Solution:
The slope - intercept form equation of line is given as
y=mx+c --- eqn (1)
Where m is the slope of the line. The coefficient of “x” is the value of slope of the line.
c is the y – intercept which is the value of y at the point where the line crosses the y-axis
a) Given that
3x+4y-12=0 --- eqn (2)
On converting equation (2) in slope intercept form, we get
4y=-3x+12
[tex]y=-\frac{3}{4} x+\frac{12}{4}[/tex]
[tex]y=-\frac{3}{4} x+3 --- eqn 3[/tex]
On comparing equation (3) and (1) we get slope of equation (2) is [tex]m=-\frac{3}{4}[/tex] and y-intercept is 3.
b) Given that
2x+y=1 …(4)
On converting equation (2) in slope intercept form, we get
y=-2x+1 …(5)
On comparing equation (5) and (1) we get slope of equation (4) is m=-2 and y-intercept is 1.
C)Given that
2x-y=0 …(6)
On converting equation (6) in slope intercept form, we get
y=2x …(7)
On comparing equation (7) and (1) we get slope of equation (6) is m=2 and y-intercept is 0.
