How many seconds are required to produce 4.00 g of aluminum metal from the electrolysis of molten AlCl3 with an electrical current of 12.0 A? How many seconds are required to produce 4.00 g of aluminum metal from the electrolysis of molten AlCl3 with an electrical current of 12.0 A? 3.57 × 103 1.19 × 103 9.00 2.90 × 105 27.0

Respuesta :

Answer:

A=[tex]3.5 x10^3 s[/tex]

Step-by-step explanation:

  • Write the electrolysis reaction for Al

[tex]Al^+^3 +3e^- -----> Al[/tex]

  • Find moles of Al using the molecular weight of Aluminum (26.981 g/mol)

[tex]4 g Al (\frac{1 mol Al}{26.981 g Al}) =0.148 mol Al[/tex]

  • Calculate moles of charge using the relation of the electrolysis reaction.

[tex]1 mol Al -----> 3 mol (e^-)[/tex]

[tex]0.148 mol Al(\frac{3 mol e^-}{1 mol Al} )=0.444 mol (e^-)[/tex]

  • Using Faraday's Constant to calculate the quantity of electricity (Coulombs)

[tex]0.444 mol (e^-)(\frac{96500 C}{1 mol (e^-)} )=42846 C[/tex]

  • Finally, you can obtain the seconds using electrical current of 12 A (12 C/s)

[tex]42846 C (\frac{1 s}{12 C} )=3570.5 s=3.57x10^3 s[/tex]