Answer:
A) 0.15
B) 0.36
Step-by-step explanation:
First Box consist 1 red pills and 19 blue pills
second box consist 6 red pills and 14 blue pills
Third box consist 2 red pills and 18 blue pills
a) Prob ( randomly chosen pill is red) [tex]= \frac{1}{3} \times \frac{1}{20} + \frac{1}{3} \times \frac{6}{20} + \frac{1}{3} \times \frac{2}{20}[/tex]
[tex]\frac{1}{60} (1+6+2) = 0.15[/tex]
b)Prob ( 1 reds and 10 blue pilss) =[tex]\frac{1}{3} \frac{^1C_1\times ^{19}C_{10}}{^{20}C_{11}} + \frac{1}{3} \frac{^6C_1\times ^{14}C_{10}}{^{20}C_{11}} + \frac{1}{3} \frac{^2C_1\times ^{18}C_{10}}{^{20}C_{11}}[/tex]
[tex]= \frac{1}{3} 1.106 = 0.368[/tex]
