Let x = big number
Let y = small number
x + y = 66...Equation A
2y = x + 15...Equation B
We have two equations in two unknowns.
x + x + 15 = 66
2x = 66 - 15
2x = 54
x = 54/2
x = 27
Plug x = 27 into EITHER equation above to find y.
I will use Equation A.
x + y = 66
27 + y = 66
y = 66 - 27
y = 39
The two numbers are 27 and 39.
Answer:
Numbers are 27 , 39.
Step-by-step explanation:
Given : The sum of two numbers is 66. two times the smaller number is 15 more then the larger number .
To find : what are the numbers.
Solution : We have given sum of two numbers is 66
Let the smaller number = x
Larger number = y.
According to question :
two times the smaller number is 15 more then the larger number .
Two times the smaller number =2x
15 more than the larger number y + 15.
2x = y + 15.
Now subtract 15 form both sides
y = 2x - 15.
Second condition :
Sum of two number is 66.
x + y =66
Now plug the y =2x -15.
x + 2x -15 = 66
3x -15 = 66.
On adding both sides by 15
3x = 66 + 15.
3x = 81
On dividing both sides by 3
x = 27.
Then , 27 + y = 66.
On subtracting both sides by 27.
y = 39.
Therefore, Numbers are 27 , 39.
