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A shell is fired from the ground with an initial speed of 1.57 ✕ 103 m/s at an initial angle of 38° to the horizontal. (a) Neglecting air resistance, find the shell's horizontal range. 122000 Incorrect: Your answer is incorrect. m (b) Find the amount of time the shell is in motion. 98.6 Incorrect: Your answer is incorrect. s

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Answer:

a) Shell's horizontal range = 243798.70 m

b) The amount of time the shell is in motion = 197.06 s

Explanation:

Consider the vertical motion of projectile,

      We have equation of motion s = ut + 0.5 at²

              Initial velocity, u = 1.57 x 10³ sin 38 = 966.59 m/s

              Acceleration, a = -9.81 m/s²

              Displacement is zero when the shell reaches back to ground, s = 0 m

              Time, t =?

      Substituting,

              s = ut + 0.5 at²

              0 = 966.59 x t + 0.5 x (-9.81) x t²

              t = 197.06 seconds

b) The amount of time the shell is in motion = 197.06 s

a) Consider the horizontal motion of shell

              We have equation of motion s = ut + 0.5 at²

              Initial velocity, u = 1.57 x 10³ cos 38 = 1237.18 m/s

              Acceleration, a = 0 m/s²

              Displacement, s = ?

              Time, t = 197.06 s

      Substituting,

              s = ut + 0.5 at²

              s = 1237.18 x 197.06 + 0.5 x 0 x 197.06²

              s =243798.70 m

   Shell's horizontal range = 243798.70 m

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