Answer:
at t=20 the second derivative switches from positive to negative
Explanation:
s(t) denotes the position in time
s'(t) the first derivative denotes the speed in time
s''(t) the second derivative, the one we want denotes the acceleration
From T=0 to T=10 the acceleration is 0.
From T=10 to T=20 the acceleration is positive
at T=20 the acceleration switches from positive to negative
at T=30 the acceleration becomes even more negative
and at T=40 the acceleration becomes 0