Respuesta :
Answer : The molar mass of benzyl acetate is 151.25 g/mol
Explanation :
Formula used for Elevation in boiling point :
[tex]\Delta T_b=i\times k_b\times m[/tex]
or,
[tex]T_b-T^o_b=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}[/tex]
where,
[tex]T_b[/tex] = boiling point of solution = [tex]61.82^oC[/tex]
[tex]T^o_b[/tex] = boiling point of chloroform = [tex]61.70^oC[/tex]
[tex]k_b[/tex] = boiling point constant of chloroform = [tex]3.63^oC/m[/tex]
m = molality
i = Van't Hoff factor = 1 (for non-electrolyte)
[tex]w_2[/tex] = mass of solute (Benzyl acetate) = 0.125 g
[tex]w_1[/tex] = mass of solvent (chloroform) = 25.0 g
[tex]M_2[/tex] = molar mass of solute (Benzyl acetate) = ?
Now put all the given values in the above formula, we get:
[tex](61.82-61.70)^oC=1\times (3.63^oC/m)\times \frac{(0.125g)\times 1000}{M_2\times (25.0g)}[/tex]
[tex]M_2=151.25g/mol[/tex]
Therefore, the molar mass of benzyl acetate is 151.25 g/mol
