2)
Which situation is represented by the equation?

0.05(x + 4) + 0.10(x) = 1.25
A) Jacob has four more dimes than nickles in his pocket, for a total of $1.25. What is x, the number of dimes in his pocket?
B) Jacob has four more nickels than dimes in his pocket, for a total of $1.25. What is x, the number of dimes in his pocket?
C) Jacob has four times the number of dimes than nickles in his pocket, for a total of $1.25. What is x, the number of dimes in his pocket?
D) Jacob has four times the number of nickels than dimes in his pocket, for a total of $1.25. What is x, the number of dimes in his pocket?

The equation is multiplying the number of dimes (x) by the value of a dime 0.10. it is also adding 4 to the value of x ( 4 more nickels than dimes) and multiplying that by the value of a nickel.

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wifilethbridge wifilethbridge · Answer 2 · 2019-10-22T10:15:17+02:00

Answer:

Given equation : [tex]0.05(x + 4) + 0.10(x) = 1.25[/tex]

1 dime = $0.10

1 nickel = $0.05

So, x is the no. of dimes in equation and x+4 is the number of nickels

So, Option B is true Jacob has four more nickels than dimes in his pocket, for a total of $1.25.

[tex]0.05(x + 4) + 0.10(x) = 1.25[/tex]

[tex]0.05x +0.2 + 0.10x = 1.25[/tex]

[tex]0.15x +0.2= 1.25[/tex]

[tex]0.15x = 1.25-0.2[/tex]

[tex]0.15x = 1.05[/tex]

[tex]x = \frac{1.05}{0.15}[/tex]

[tex]x =7[/tex]

Hence the number of dimes in his pocket is 7