Answer:
The value that must be added to both sides of the equation is 9/64
Step-by-step explanation:
we have
[tex]x^{2} -\frac{3}{4}x=5[/tex]
Divide the term -3/4 by 2
[tex]\frac{(-3/4)}{2}=-\frac{3}{8}[/tex]
squared the term (-3/8)
[tex](-\frac{3}{8})^{2}=\frac{9}{64}[/tex]
Adds the term 9/64 both sides of the equation
[tex]x^{2} -\frac{3}{4}x+\frac{9}{64}=5+\frac{9}{64}[/tex]
Rewrite as perfect square
[tex](x-\frac{3}{8})^{2}=\frac{329}{64}[/tex]
therefore
The value that must be added to both sides of the equation is 9/64
