Answer:
Step-by-step explanation:
Use the point-slope formula by the line
y - y_1 = m(x - x_1) when x_1 =8 and y_1 = -2 m : is the slope (same slope for the line whose equation is 3x + 4y = 15 because are parallel)
calculate : m
3x + 4y = 15
4y = -3x +15
y = (-3/4)x +15/4 so m = -3/4
an equation is : y +2 =(-3/4)(x-8)
Answer:
The required equation of line is [tex]3x+4y=16[/tex]
Step-by-step explanation:
Given : A line that passes through the point (8, -2) and is parallel to the line whose equation is [tex]3x + 4y = 15[/tex]
To find : What is the equation of a line ?
Solution :
We know that,
When two lines are parallel then their slopes are equal.
The equation of line is [tex]3x + 4y = 15[/tex]
Convert into slope form [tex]y=mx+c[/tex],
[tex]4y =-3x+ 15[/tex]
[tex]y=\frac{-3x+15}{4}[/tex]
[tex]y=-\frac{3}{4}x+\frac{15}{4}[/tex]
The slope of the line is [tex]m=-\frac{3}{4}[/tex]
The line passes through (8,-2).
The general point slope form is [tex](y-y_1)=m(x-x_1)[/tex]
i.e. [tex](y-(-2))=-\frac{3}{4}(x-8)[/tex]
[tex]y+2=-\frac{3}{4}(x-8)[/tex]
[tex]4y+8=-3x+24[/tex]
[tex]3x+4y=16[/tex]
Therefore, the required equation of line is [tex]3x+4y=16[/tex]
