Answer:
There will be 600 tall plants in that generation.
Explanation:
In Mendel’s cross the selected parents are a tall pea plant and a short pea plant. Both the parents are homozygous. The recessive trait is short. Letter T represents tall and t represents short. Hence the phenotype TT is homozygous dominant and tt is homozygous recessive.
The genotype Tt represents tall since T is dominant over t. Mendel’s cross can be represented as
[tex]Tall \times Short[/tex]
[tex]TT \times tt[/tex]
F1 generation Tt Tt Tt Tt
F2 generation TT Tt Tt tt
In the F1 generation all the plants are tall and in the F2 generation 3/4 plants are tall and1/4 plants are short.
In the question it is given that 200 plants are short in the F2 generation. Let total number of offspring in the F2 generation is x.
[tex]1/4 \times x=200[/tex]
x=800
number of tall plants = [tex]3/4 \times x[/tex]
[tex]= 3/4 \times 800 =600[/tex]
Hence there will be 600 tall plants in the F2 generation.
