Answer:
The length of the other leg of triangle is [tex]4\sqrt{7}\ units[/tex]
Step-by-step explanation:
we know that
A right triangle must satisfy the Pythagoras theorem
[tex]c^{2}=a^2+b^2[/tex]
where
c is the hypotenuse (the greater side)
a and b are the legs
we have
[tex]a=3\ units\\c=11\ units[/tex]
substitute in the formula and solve for b
[tex]11^{2}=3^2+b^2[/tex]
[tex]121=9+b^2[/tex]
[tex]b^2=121-9[/tex]
[tex]b^2=112[/tex]
[tex]b=\sqrt{112}\ units[/tex]
simplify
[tex]b=4\sqrt{7}\ units[/tex]
