Answer: 0.0278
Step-by-step explanation:
On a fair dice , there are six numbers (1,2,3,4,5,6) written on each face of dice.
Thus, when we thrown two dice , the sample space for the possibilities of outcomes will become :
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
i.e. Total number of outcomes = 36
For event A: { 3 appears on each of two dice.}
The favorable outcome = (3,3)
Now, the required probability : [tex]P(A)=\dfrac{\text{Number of favorable outcomes}}{\text{Total outcomes}}[/tex]
[tex]=\dfrac{1}{36}=0.0277777777778\approx0.0278[/tex]
Hence, the required probability is 0.0278.
