Respuesta :
Answer:
There is 9671 Kj of heat released
Explanation:
Step 1: The balanced equation:
C18H36O2(s) + 26O2(g) --> 18CO2(g)+18H2O(g)
This means for 1 mole of C18H36O2 consumed there is 26 moles of O2 needed to produce 18 moles of CO2 and 18 moles of H2O.
Step 2: Calculate the heat of combustion
ΔH (combustion) = [18*(ΔHf of CO2) + 18*(ΔHf of H2O)] - [1*(ΔHf of C18H36O2) + 26*(ΔHf of O2)]
ΔH (combustion) = [18*(-394 kJ/mol) + 18*(-242 kJ/mol)] - [1*(-948 kJ/mol) + 26*(0 kJ/mol)]
ΔH (combustion) = [(-7092 kJ/mol) + (-4356 kJ/mol)] - (-948 kJ/mol)
= -10500 kJ/mol
ΔH (combustion) = heat released / number of moles of stearic acid
Step 3: Calculate moles of stearic acid
moles of stearic acid = mass / Molar mass of stearic acid
moles of stearic acid = 262g / 284.48 g/mole = 0.921 moles
Step 4: Calculate moles of oxygen
moles of O2 = 914.5 / 32g/mole
moles of O2 = 28.578125 moles
Stearic acid is the limiting reactant: it will completely react
There will react 26*0.921 mole = 23.946 mole of O2
This means there will remain 4.63 moles of O2
Step 5: Calculate heat released
q = (ΔH combustion) * (moles of stearic acid) = (-10500 kJ/mol) * (0.921 moles) = 9671 Kj
There is 9671 Kj of heat released
The study of chemicals and bonds is called chemistry. There are two types of elements and these are metals and nonmetals.
The correct answer is 9671 Kj of heat released
What is a hydrocarbon?
- Hydrocarbon, any of a class of organic chemical compounds composed only of the elements carbon and hydrogen
Step 1: The balanced equation:
[tex]C_18H_36O_2(s) + 26O_2(g) --> 18CO_2(g)+18H_2O(g)[/tex]
This means for 1 mole of C18H36O2 consumed there is 26 moles of O2 needed to produce 18 moles of CO2 and 18 moles of H2O.
Step 2: Calculate the heat of combustion
ΔH (combustion) =[tex][18*(ΔHf of CO2) + 18*(ΔHf of H2O)] - [1*(ΔHf of C18H36O2) + 26*(ΔHf of O2)][/tex]
ΔH (combustion) = [tex][18*(-394 kJ/mol) + 18*(-242 kJ/mol)] - [1*(-948 kJ/mol) + 26*(0 kJ/mol)][/tex]
ΔH (combustion) = [tex][(-7092 kJ/mol) + (-4356 kJ/mol)] - (-948 kJ/mol) = -10500 kJ/mol[/tex]
ΔH (combustion) = heat released / number of moles of stearic acid
Step 3: Calculate moles of stearic acid
moles of stearic acid = mass / Molar mass of stearic acid
moles of stearic acid = [tex]\frac{262g}{284.48} = 0.921 moles[/tex]
Step 4: Calculate moles of oxygen
moles of O2 =[tex]\frac{914.5}{32g}[/tex]/mole
moles of O2 = 28.578125 moles
Stearic acid is the limiting reactant: it will completely react
There will react 26*0.921 mole = 23.946 mole of O2
This means there will remain 4.63 moles of O2
Step 5: Calculate heat released
q = (ΔH combustion) * (moles of stearic acid) = [tex](-10500 kJ/mol) * (0.921 moles) = 9671 Kj[/tex]
Hence, There is 9671 Kj of heat released.
For more information about the hydrocarbon, refer to the link:-
https://brainly.com/question/7932885