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100.000g of water at 80.0oC was mixed with an equal amount of cool water in a calorimeter. The final temperature of the water in the calorimeter is 50.0oC. What is the heat (q) in kilojoules for the hot water? (specific heat for water is 4.18J/goC).

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joseaaronlara

Answer:

The answer to your question is: Q = 12540 kJ

Explanation:

Data

mass = 100,000 g

Cp = 4.18 /g°C

T1 = 80°C

T2 = 50°C

Formula

                       [tex]Q = mCp(T2 - T1)[/tex]

                       Q = (100000)(4.18)( 50 - 80)

                       Q = - 12540000 J

                       Q = 12540 kJ

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