Answer:
(a) Bus will traveled further a distance of 40 m
(b) It will take 7.5 sec to stop the bus
Explanation:
We have given initial velocity of the bus u = 24 m/sec
And final velocity v = 16 m/sec
Distance traveled in this process s = 50 m
From third equation of motion we know that [tex]v^2=u^2+2as[/tex]
[tex]16^2=24^2+2\times a\times 50[/tex]
[tex]a=-3.2m/sec^2[/tex]
(a) Now as the bus finally stops so final velocity v = 0 m/sec
So [tex]v^2=u^2+2as[/tex]
[tex]0^2=24^2-2\times 3.2\times s[/tex]
s= 90 m
So further distance traveled by bus = 90-50 =40 m
(b) Now as the bus finally stops so final velocity v= 0 m/sec
Initial velocity u = 24 m/sec
Acceleration [tex]a=-3.2m/sec^2[/tex]
So time [tex]t=\frac{v-u}{a}=\frac{0-24}{-3.2}=7.5sec[/tex]
