Answer:
[tex]v_{avg} = 5\ m/s[/tex]
displacement = 100 m
Explanation:
given,
initial velocity of cart = 10 m/s
golf cart is slowly decelerating
time taken to stop = 20 s
final velocity = 0 m/s
using equation of motion
v = u + a t
0 = 10 - a× 20
a = 0.5 m/s²
[tex]Average\ velocity = \dfrac{total\ displacement}{total\ time}[/tex]
total displacement
v² = u² + 2 a s
0 = 10² - 2 × 0.5 ×s
s = 100 m
now,
[tex]Average\ velocity = \dfrac{total\ displacement}{total\ time}[/tex]
[tex]v_{avg} = \dfrac{100}{20}[/tex]
[tex]v_{avg} = 5\ m/s[/tex]
