What is the angle of refraction if a ray leaves a material with an index of 1.66, traveling into air, and the angle of incidence is 37 deg?

Respuesta :

Answer:

  [tex]r = 21.26^0 [/tex]

Explanation:

given,

light is incident on the plane surface at (i) = 37°

angle of refraction (r) = ?                        

μ is the refractive index of the  material      

      μ = 1.66      

using Snell's law                

  [tex]\mu = \dfrac{sin i}{sin r}[/tex]                

  [tex]1.66 = \dfrac{sin 37^0}{sin r}[/tex]                      

  [tex]sin r = \dfrac{sin 37^0}{1.66}[/tex]    

  [tex]sin r = 0.362[/tex]      

  [tex]r = 21.26^0 [/tex]  

hence. the angle of refraction is equal to [tex]r = 21.26^0 [/tex]