contestada

A bar-magnet with magnetic moment 2.5 Am^2 is placed in a homogeneous magnetic field (of 0.1 T that is directed along the z-axis). What force and torque will the bar-magnet experience due to the magnetic field if: a) The north-pole of the magnet is pointing along the z-axis?
b) The north-pole of the magnet is pointing 45° relative to the z-axis?
c) The north-pole of the magnet is pointing 90° relative to the z-axis?

Respuesta :

Answer:

1)

Force on bar magnet  = 0

Torque on bar magnet = 0

2)

Force on bar magnet  = 0

Torque on bar magnet = 0.177 Nm

3)

Force on bar magnet  = 0

Torque on bar magnet = 0.25 Nm

Explanation:

Part 1)

net force on bar magnet in uniform magnetic field is always zero

Torque on bar magnet is given as

[tex]\tau = MBsin\theta[/tex]

when bar magnet is inclined along z axis along magnetic field

then we will have

[tex]\tau = MBsin0 = 0[/tex]

Part 2)

net force on bar magnet in uniform magnetic field is always zero

Torque on bar magnet is given as

[tex]\tau = MBsin\theta[/tex]

when bar magnet is pointing 45 degree with z axis then we will have

[tex]\tau = MBsin45 [/tex]

[tex]\tau = (2.5)(0.1)sin45[/tex]

[tex]\tau = 0.177 Nm[/tex]

Part 3)

net force on bar magnet in uniform magnetic field is always zero

Torque on bar magnet is given as

[tex]\tau = MBsin\theta[/tex]

when bar magnet is pointing 90 degree with z axis then we will have

[tex]\tau = MBsin90 [/tex]

[tex]\tau = (2.5)(0.1)sin90[/tex]

[tex]\tau = 0.25 Nm[/tex]