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Sally wants to buy her friend a bouquet for his birthday. She wants it to contain both carnations and roses. She has $27.30 to spend. Carnations cost $1.42 each and roses cost $2.35 each. Which graph below represents the possible combinations of numbers of carnations and roses Sally can afford to buy?​

Sally wants to buy her friend a bouquet for his birthday She wants it to contain both carnations and roses She has 2730 to spend Carnations cost 142 each and ro class=

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joseaaronlara

Answer:

The answer to your question is: letter A

Step-by-step explanation:

Data

Total cost = $27.30

carnations = $1.42 = x

roses = $2.35 = y

Equation

               1.42x + 2.35y = 27.30

Solve for y

                    2.35y = -1.42x + 27.30

                           y = -(1.42/2.35) + (27.30/2.35)

                           y = -0.604x + 11.61

Find x and y-intercepts

When x = 0          y = -0.604(0) + 11.61

                            y = 11.61

Point     (0, 11.61)

When y = 0

                        0 = -0-604x + 11.61

                       x = 11.61/ -0.604

                      x = 19.22

Point (19.22, 0)

Look for which graph has these 2 points.

I think is letter A

Answer:

Graph D

Step-by-step explanation:

27.30 / 1.42 ≈ 19 (carnations max)

27.30 / 2.35 ≈ 11 (roses max)

HOWEVER, she wants it to contain BOTH carnations AND roses.

Therefore, we need to adjust our equation to include at least one of the other plants.

(27.30 - 2.35) / 1.42 ≈ 17 (carnations max)

(27.30 - 1.42) / 2.35 ≈ 10 (roses max)

Only graph D touches 17 carnations and 1 rose; and 10 roses and 1 carnation with a minimum of one for both plants.

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