Answer:[tex]179.79 \times 10^{-9} J[/tex]
Explanation:
Given
Separation (d)=4 mm
Area of cross-section[tex]=25 cm^2[/tex]
Potential difference=255 V
[tex]C=\frac{\epsilon A}{d}=5.53 \times 10^{-12}F[/tex]
charge [tex](Q)=CV=5.53\times 225=1411.10\times 10^{-12} C[/tex]
Energy stored[tex]=\frac{cv^2}{2}[/tex]
[tex]E=\frac{5.53\times 10^{-12} 255^2}{2}=179.79 \times 10^{-9} J[/tex]
