Answer:
The graph in the attached figure
Step-by-step explanation:
we know that
The equation of a line in point slope form is
[tex]y-y1=m(x-x1)[/tex]
we have
[tex](x_1,y_1)=(6,3)[/tex]
[tex]m=\frac{1}{4}[/tex]
substitute
[tex]y-3=\frac{1}{4}(x-6)[/tex]
The easiest way to graph a line is to calculate the intercepts
The x-intercept is the value of x when the value of y is equal to zero
For y=0
[tex]0-3=\frac{1}{4}(x-6)[/tex]
[tex]-12=(x-6)[/tex]
[tex]x=-12+6=-6[/tex]
The x-intercept is the point (-6,0)
The y-intercept is the value of y when the value of x is equal to zero
For x=0
[tex]y-3=\frac{1}{4}(0-6)[/tex]
[tex]y-3=-\frac{3}{2}[/tex]
[tex]y=-\frac{3}{2}+3[/tex]
[tex]y=1.5[/tex]
The y-intercept is the point (0,1.5)
Plot the intercepts and join the points to graph the line
(-6,0) and (0,1.5)
The graph in the attached figure
