a laboratory, you determine that the density of a certain solid is 5.23×10−6kg/mm3. Convert this density into kilograms per cubic meter. Notice that the units you are trying to eliminate are now in the denominator. The same principle from the previous parts applies: Pick the conversion factor so that the units cancel. The only change is that now the units you wish to cancel must appear in the numerator of the conversion factor

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pinquancaro pinquancaro · Answer 1 · 2019-10-10T07:42:01+02:00

Answer:

[tex]5.23\times 10^{-6}\ kg/mm^3=5230\ kg/m^3[/tex]

Step-by-step explanation:

Given : The density of a certain solid is [tex]5.23\times 10^{-6}[/tex] kg/mm³.

To find : Convert this density into kilograms per cubic meter ?

Solution :

We know that,

[tex]1\ m^3=10^9\ mm^3[/tex]

or [tex]10^9\ mm^3=1\ m^3[/tex]

So, [tex]1 mm^3=\frac{1}{10^9}\ m^3[/tex]

[tex]1 mm^3=10^{-9}\ m^3[/tex]

Converting [tex]5.23\times 10^{-6}[/tex] kg/mm³ into kg/m³,

[tex]5.23\times 10^{-6}\ kg/mm^3=\frac{5.23\times 10^{-6}}{10^{-9}}\ kg/m^3[/tex]

[tex]5.23\times 10^{-6}\ kg/mm^3=5.23\times 10^{-6+9}\ kg/m^3[/tex]

[tex]5.23\times 10^{-6}\ kg/mm^3=5.23\times 10^{3}\ kg/m^3[/tex]

[tex]5.23\times 10^{-6}\ kg/mm^3=5230\ kg/m^3[/tex]

Therefore, [tex]5.23\times 10^{-6}\ kg/mm^3=5230\ kg/m^3[/tex]