Answer:
a)[tex]a=-7.4\times 10^{-5}\ m/s^2[/tex]
b)[tex]t=0.27\times 10^{-3}\ s[/tex]
c)s=14.92 cm
Explanation:
Given that
u= 470 m/s
v = 270 m/s
s= 10 cm
a)
We know that
[tex]v^2=u^2+2as[/tex]
[tex]270^2=470^2+2\times a\times 0.1[/tex]
[tex]a=-7.4\times 10^{-5}\ m/s^2[/tex]
b)
v= u + a t
[tex]270=470-7.4\times 10^{-5}\times t[/tex]
[tex]t=0.27\times 10^{-3}\ s[/tex]
c)
To stop the bullet it means that the final velocity will be zero.
[tex]v^2=u^2+2as[/tex]
[tex]0^2=470^2-2\times 7.4\times 10^{-5} \times s[/tex]
s=14.92 cm