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Complete the following precipitation reaction with balanced molecular, total ionic, and net ionic equations. Remember to include the proper physical states and charges of ions. When writing ions, if a charge number is not "1", place the charge number before the charge sign. If a charge number is "1", do not include the charge number in the formula. Na2S(aq) + ZnSO4(aq) →

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Molecular equation (includes all species in the molecular form)

Na₂S(aq) + ZnSO₄(aq) → Na₂SO₄(aq) + ZnS(s)

Total ionic equation (includes all ions. Insoluble solids do not dissociate)

2 Na⁺(aq) + S²⁻(aq) + Zn²⁺(aq) + SO₄²⁻(aq) → 2 Na⁺(aq) + SO₄²⁻(aq) + ZnS(s)

Net ionic equation (includes only ions that participate in the reaction, that is, it does not include spectator ions)

S²⁻(aq) + Zn²⁺(aq) → ZnS(s)

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A. The balanced molecular equation is

Na₂S(aq) + ZnSO₄(aq) → Na₂SO₄(aq) + ZnS(s)

B. The total ionic equation is

2Na⁺(aq) + S²⁻(aq) + Zn²⁺(aq) + SO₄²⁻(aq) → 2Na⁺(aq) + SO₄²⁻(aq) + ZnS(s)

C. The net ionic equation is

S²⁻(aq) + Zn²⁺(aq) → ZnS(s)

A. How to determine the molecular equation

When sodium sulphide, Na₂S reacts with zinc sulphate, ZnSO₄, it will produce sodium sulphate Na₂SO₄ and zinc sulphide, ZnS according to the following equation:

Na₂S(aq) + ZnSO₄(aq) → Na₂SO₄(aq) + ZnS(s)

B. How to determine the total ionic equation

In solution,

Na₂S(aq) → 2Na⁺(aq) + S²⁻(aq)

ZnSO₄(aq) → Zn²⁺(aq) + SO₄²⁻(aq)

Na₂S(aq) + ZnSO₄(aq) →

2Na⁺(aq) + S²⁻(aq) + Zn²⁺(aq) + SO₄²⁻(aq) → 2Na⁺(aq) + SO₄²⁻(aq) + ZnS(s)

C. How to determine the net ionic equation

2Na⁺(aq) + S²⁻(aq) + Zn²⁺(aq) + SO₄²⁻(aq) → 2Na⁺(aq) + SO₄²⁻(aq) + ZnS(s)

Cancel out the spectator ions (i.e Na⁺ and SO₄²⁻) to obtain the net ionic equation

S²⁻(aq) + Zn²⁺(aq) → ZnS(s)

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