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The field from a large plate A is 1180 N/C pointing eastward, while another plate B produces a field that is 1520 N/C northward. What is the net field produced by the combination?
?N/C
An object has been charged to 480 μC and placed in the field.
What is the magnitude of the force on the object?
? N

Respuesta :

Answer:

E=1924.26 N/C

F=0.92 N

Explanation:

As we know that electric field is a vector quantity.It means that it have direction.

Plate A

E(A) = 1180 N/C  ,Eastward

Plate B

E(B) =1520 N/C ,Northward

The resultant electric field given as

[tex]E=\sqrt{E_A^2+E_B^2}\ N/C[/tex]

[tex]E=\sqrt{1180^2+1520^2}\ N/C[/tex]

E=1924.26 N/C

We know that

F = q E

Here q =480 μC

E=1924.26 N/C

By putting the values

F = q E

[tex]F=480\times 10^{-6}\times 1924.26\ N[/tex]

F=0.92 N

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