Answer:
a) t = 0.528 s
b) D = 1.62 m
Explanation:
given,
speed of the baseball = 3.75 m/s
angle made with the horizontal = 35°
height of the roof edge = 2.5 m
using equation of motion
[tex]s = ut +\dfrac{1}{2}gt^2[/tex]
[tex]2.5 = vsin\theta \ t +\dfrac{1}{2}gt^2[/tex]
[tex]2.5 = 3.75\ sin35^0 \ t +\dfrac{1}{2}\times 9.8 t^2[/tex]
4.9 t² + 2.15 t - 2.5 = 0
on solving the above equation
t = 0.528 s
b) D = v cos θ × t
D = 3.75 × cos 35° ×0.528
D = 1.62 m
