Answer:
[tex]a=708.3m/s^2[/tex]
Explanation:
The force experimented by a charge q in a uniform electric field E is F=qE.
Newton's 2nd Law tells us that the relation between acceleration a a mass m experiments when a force F is applied to it is F=ma.
Combining these equations we have am=qE, and since we want the acceleration of the speck of dust, we substitute our values:
[tex]a=\frac{qE}{m}=\frac{(10\times10^{-6}C)(850N/C)}{12\times10^{-6}Kg}=708.3m/s^2[/tex]
