A car moving in a straight line starts at x = 0 at t = 0 . It passes the point x = 30.0 m with a speed of 10.0 m/s at t = 3.00 s . It passes the point x = 375 m with a speed of 50.0 m/s at t = 20.0 s . Find the average velocity between t = 3.00 s and t = 20.0 s . Express your answer with the appropriate units.
Find the average acceleration between t = 3.00 s and t = 20.0 s .
Express your answer with the appropriate units.

Respuesta :

Answer:

a) [tex]v=20.3m/s[/tex]

b) [tex]a=2.35m/s^2[/tex]

Explanation:

From the exercise we know:

[tex]x_{1}=30m[/tex]; [tex]v_{1}=10m/s[/tex]; [tex]t_{1}=3s[/tex]

[tex]x_{2}=375m[/tex]; [tex]v_{2}=50m/s[/tex]; [tex]t_{2}=20s[/tex]

The formula for average velocity is:

[tex]v=\frac{x_{2}-x_{1}}{t_{2}-t_{1}}[/tex]

a) [tex]v=\frac{375m-30m}{20s-3s}=20.3m/s[/tex]

The formula for average acceleration is:

[tex]a=\frac{v_{2}-v_{1}}{t_{2}-t_{1}}[/tex]

b) [tex]a=\frac{(50-10)m/s}{(20-3)s}=2.35m/s^2[/tex]