Answer:
a) [tex]d=187.6km[/tex]
b)[tex]v=61.5km/h[/tex]
Explanation:
First we convert our minutes to hours so we work always in the same units.
[tex]36min=36min(\frac{1h}{60min})=0.6h[/tex]
[tex]15min=15min(\frac{1h}{60min})=0.25h[/tex]
Where we used the fact that 1 hour are 60 min, thus the multiplying factor is equal to 1 (not altering the time, just changing the units).
a) On the first part the motorist travels a distance [tex]d_1=v_1t_1=(96km/h)(0.6h)=57.6km[/tex], and on the second part he travels [tex]d_2=130km[/tex].
The total displacement is [tex]d=d_1+d_2=57.6km+130km=187.6km[/tex]
b) The average velocity is the relation between the total displacement and the time taken to cover it. Our total time is t=0.6h+0.25h+2.2h=3.05h, thus we have:
[tex]v=\frac{187.6km}{3.05h}=61.5km/h[/tex]
