A water balloon is thrown at an angle of 30° with a velocity of 40 m/s. How long do you have to move out of the way if the balloon was 20m away from you when it was thrown?

Respuesta :

AMB000

Answer:

t=0.58s

Explanation:

We can consider only the horizontal component since the horizontal component of the velocity is constant ([tex]v_x=vcos\theta[/tex]), and we want to know how much time it takes for the balloon to travel a horizontal distance [tex]d_x[/tex] at that speed. The definition of (horizontal) velocity is [tex]v_x=\frac{d_x}{t}[/tex], so we have:

[tex]t=\frac{d_x}{v_x}=\frac{d_x}{vcos\theta}=\frac{(20m)}{(40m/s)cos(30^{\circ})}=0.58s[/tex]