Answer:
a) a= 0.3 m/s²
b) v₀ = 5 m/s
c) t_f= 0
Explanation:
Because acceleration is constant:
a= Δv/Δt =( vf-v₀)/(t_f-t₀) Formula (1)
a: acceleration (m/s²)
vf : final speed (m/s)
v₀ : initial speed (m/s)
t_f : final time (s)
t₀ : initial time (s)
Problem development
a) We apply Formula (1)
a= Δv/Δt = ( vf-v₀)/(t_f-t₀)
[tex]a= \frac{8-5}{20-10} =\frac{3}{10} = 0.3 \frac{m}{s^{2} }[/tex]
b) v₀: initial speed (m/s)
v₀ = 5 m/s
c) t_f : final time (s) , vf=0 a= 0.3 m/s²
a= ( vf-v₀)/(t_f-t₀)
0.3= ( 0-3)/(t_f-10)
(t_f-10) (0.3) = -3
0.3t_f+ 3 = -3
t_f= 0
