Answer:
Kinetic energy of the electron [tex]E_k=1.23\ eV[/tex]
Explanation:
It is given that,
Initial speed of an electron, u = 660000 m/s
Final speed of the electron, v = 0 (at rest)
The kinetic energy of an electron is possessed due to the motion of an electron. The mathematical formula for the kinetic energy is given by :
[tex]E_k=\dfrac{1}{2}mv^2[/tex]
m is the mass of electron
[tex]E_k=\dfrac{1}{2}\times 9.1\times 10^{-31}\times (660000)^2[/tex]
[tex]E_k=1.98\times 10^{-19}\ J[/tex]
Since, [tex]1\ eV=1.602\times 10^{-19}\ J[/tex]
[tex]E_k=\dfrac{1.98\times 10^{-19}}{1.602\times 10^{-19}}[/tex]
[tex]E_k=1.23\ eV[/tex]
So, the initial kinetic energy of the electron is 1.23 eV. Hence, this is the required solution.
