Answer:
[tex]W_{wing} = 301.5 J[/tex]
Explanation:
As we know by work energy theorem that net work done by all forces is equal to change in kinetic energy
so here we can say
[tex]W_{wing} + W_{gravity} + W_{drag} = \frac{1}{2}m(v_f^2 - v_i^2)[/tex]
now we know that when plane moves upwards then
[tex]W_{gravity} = -mgh[/tex]
[tex]W_{gravity} = 0.300(-9.8)(50 - 10)[/tex]
[tex]W_{gravity} = -117.6 J[/tex]
Now work done by drag force is given as
[tex]W_{drag = -F_{drag} \frac{h_2 - h_1}{sin\theta}[/tex]
[tex]W_{drag} = -2.5(\frac{50- 10}{sin35})[/tex]
[tex]W_{drag} = -174.3 J[/tex]
now we have
[tex]W_{wing} - 174.3 - 117.6 = \frac{1}{2}(0.300)(10^2 - 6^2)[/tex]
[tex]W_{wing} = 301.5 J[/tex]
