Answer:
[tex]v_{x}=24.88m/s[/tex]
[tex]v_{y}=2.35m/s[/tex]
Explanation:
Knowing that the truck travels up a hill with a 5.4º incline
The horizontal component of the truck's velocity is:
[tex]v_{x}=vcos\beta=(25m/s)cos(5.4)=24.88m/s[/tex]
The vertical component of the truck's velocity is:
[tex]v_{y}=vsin\beta=(25m/s)sin(5.4)=2.35m/s[/tex]