Answer:
Explanation:
Given
Total run=198 m
maximum speed=317 m/min=5.28 m/s
acceleration[tex]=1.11 m/s^2[/tex]
(a)Distance traveled while  accelerating
[tex]v^2-u^2=2as[/tex]
[tex](5.28)^2-0=2\times 1.11\times s[/tex]
s=12.57 m
time taken
v=u+at
[tex]5.28=0+1.11\times t[/tex]
t=4.75 s
(b)Time taken to cover 198 m
if car takes 12.57 m & 4.75 s to reach max speed so it also takes 12.57 m and 4.75 s to stop from max speed
Distance traveled with max speed=198-25.14=172.86 m
time taken[tex]=\frac{172.86}{5.28}=32.73 s[/tex]
total time=4.75+32.73+4.75=42.25 s
