Answer:
Capacitance, C = 14.51 F
Explanation:
It is given that,
Area of a parallel plate capacitor, [tex]A=40\ cm^2=0.0041\ m^2[/tex]
Spacing between the plates, d = 2.5 mm = 0.0025 m
We need to find the capacitance of the parallel plate capacitor. Its formula is given by :
[tex]C=\dfrac{A\epsilon_o}{d}[/tex]
[tex]C=\dfrac{0.0041\times 8.85\times 10^{-12}}{0.0025}[/tex]
[tex]C=1.451\times 10^{-11}\ F[/tex]
[tex]C=14.51\times 10^{-12}\ F[/tex]
[tex]C=14.51\ pF[/tex]
So, the capacitance of the capacitor is 14.51 pF. Hence, this is the required solution.
