A man walks along some sidewalks in the downtown area of a city. First, he walks west by 60 m, then he walks south by 80 m. What is the difference between his traveled distance and the magnitude of his displacement?

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AMB000

Answer:

40m

Explanation:

The traveled distance is just the sum of each traveled distance:

T=60m+80m=140m

The displacement is the distance between the final point and the initial point, in this case it will be the hypotenuse of a right angle, so we calculate this distance with Pythagoras' Theorem:

[tex]D=\sqrt{(60m)^2+(80m)^2}[/tex]=100m

The difference between the traveled distance and the displacement is thus

T-D=140m-100m=40m